(가) $\lim\limits_{x \to \infty} \dfrac{f(x)}{x^2 + 1} = 1$
(나) $\lim\limits_{x \to 1} \dfrac{f(x)}{x - 1} = 3$
(가) $\lim\limits_{x \to \infty} \dfrac{f(x)}{x^2 + 1} = 2$
(나) $\lim\limits_{x \to 1} \dfrac{f(x)}{x - 1} = 8$
(가) $\lim\limits_{x \to \infty} \dfrac{f(x)}{x^2 + 1} = 3$
(나) $\lim\limits_{x \to 1} \dfrac{f(x)}{x - 1} = 15$